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what's the domain and the range of the function?

2007-12-19 09:42:34 · 4 answers · asked by hmm 3 in Science & Mathematics Mathematics

4 answers

x^2 + y = 4
y = 4 - x^2

The domain is all real numbers, (-inf, +inf), because x^2 is defined for any real number. The range is all real numbers equal to or smaller than 4, (-inf, 4], because x^2 can assume only non-negative values so y = 4 - x^2 can never be larger than 4.

2007-12-19 09:46:01 · answer #1 · answered by DavidK93 7 · 1 0

so, y=f(x)=4-x^2, a parabola facing down with vertex at (0,4).
Since f(x) is a plain quadratic, anything can go into it. But its range is only the things that lie on the good side of it, so to speak. It touches all things below 4. But it does also touch its highest point, 4.


The domain is the whole field (-inf,inf)
The range is (-inf,4]

2007-12-19 17:49:56 · answer #2 · answered by Charles R 2 · 0 0

Hi,
Range of X:
y=4-x^2
--> "x" is a real number
"x"

Range of Y:
x=sqrt(4-y)
--> 4-y>=0
--> y<=4
"y"
good luck

2007-12-19 17:48:36 · answer #3 · answered by Anonymous · 0 0

6xy=8

2007-12-19 17:46:00 · answer #4 · answered by Anonymous · 0 2

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