how do you write this in slope intercept form
2007-12-19 09:19:59 · 17 answers · asked by answertron 1 in Science & Mathematics ➔ Mathematics
y+= 5/8x+ 17/8.
PLEASE help me on this math problem!!
http://answers.yahoo.com/question/index;_ylt=AhDlAAD35fuSIvspWyjv4hzsy6IX;_ylv=3?qid=20071219140853AAEYxFr
2007-12-19 09:26:05 · answer #1 · answered by #1 padres fan 3 · 0⤊ 0⤋
slope intercept form is
y = mx + b
so
5x - 8y = -17
-8y = -17 -5x
8y = 17 + 5x
y = 5/8 x + 17 / 8
2007-12-19 17:24:04 · answer #2 · answered by soulbleed62 2 · 0⤊ 0⤋
The slope-intercept form for the equation of a line with slope M and Y-intercept (0,b) is: y = mx + b
2007-12-19 17:25:47 · answer #3 · answered by myra2025 2 · 0⤊ 0⤋
well slope itercept is y=mx + b
so you have 5x-8y=-17
-5x -5x
so now it's -8y=-5x-17
then divide -8y from the other side
like -8y=-5x-17
/-8 /-8 /-8
so now its y=-5x over -8+2.125
-5 over -8 is equal to 5 over 8 so either way its the same.
2007-12-19 17:30:09 · answer #4 · answered by Scott 2 · 0⤊ 0⤋
- 8y = -17 - 5x
8y = 17 + 5x
y = 5/8 x + 17/8
2007-12-19 17:22:55 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋
bring the 5x to the other side and divide the whole thing by -8
y= (5x-17)/-8
2007-12-19 17:22:54 · answer #6 · answered by Anonymous · 0⤊ 0⤋
y = 5x+17
2007-12-19 17:22:27 · answer #7 · answered by Jason K 5 · 0⤊ 0⤋
Solve the equation for Y in the positive.... Can you to that? Then the coefficient of x is the slope, and the real number is where the equation crosses the y-axis.
2007-12-19 17:23:27 · answer #8 · answered by April 6 · 0⤊ 0⤋
y=5/8x + 17/8
2007-12-19 17:27:32 · answer #9 · answered by Casey 2 · 0⤊ 0⤋
y=5/8x + 17/8
2007-12-19 17:22:29 · answer #10 · answered by Holly Golightly 7 · 0⤊ 0⤋
first you want the y's on one side by themselves, so you subtract 5x.
-8y = -5x - 17
next you divide by -8 to get y by itself to get
y = 5/8x + 17/8
hope i helped!
2007-12-19 17:22:17 · answer #11 · answered by lizbiz707 3 · 2⤊ 0⤋