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I had to do write these triangle inequalities and now i have to add them up, but I'm not sure how.

PY+PY>XY
PY+PZ>ZY
PX+PZ>XZ

What does that add up to be?

Thank you for your time.

2007-12-19 09:09:36 · 1 answers · asked by asdasdasdasdasdasdasdasdadasdads 2 in Science & Mathematics Mathematics

1 answers

You probably made a typo in the first one. One of those PYs should probably be a PX.

At a wild guess, I'm right about the error, and you want to add up all the LHS and all the RHS, in which case inequality still holds, and you get

2 (PX + PY + PZ) > XY+ZY+XZ

At a further wild guess, what you're trying to prove may be accomplished by dividing both sides of that by 2.

Presumably XYZ is a triangle and P is a point in its interior?

2007-12-19 13:05:13 · answer #1 · answered by Curt Monash 7 · 0 0

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