Trouble with math....?

Question

( ^ = to the power of )

Write the product as a trinomial

(p^2 – q^2)(p^2 + 3q^2)

it can be

p^4 + 2pq^2+ 2q^2
or
p^4 + 4p2q2 – 3q4
or
p^4 + 2p^2q^2 – 3q^4
or
p^4 – 4p^2q^2 – 3q^4


thank you!!!! ;)

Answer 1

p^4 + 2p^2q^2 – 3q^4

Answer 2

Start with the two left terms in each expression:
p^2 times P^2 = P^4
Then the two ends:
P^2 times 3q^2 = 3p^2q^2
then the two middles
P^2 times -q^2 = -P^2q^2
And the the right terms:
-q^2 time 3q^2 = -3q^4

so you get

P^4+3p^2q^2 -P^2q^2-3q^4
Combine like terms

p^4+2p^2q^2-3q^4

Clear?

Answer 3

p^4 + 2p^2q^2 – 3q^4. That should be the answer.

Answer 4

It's the THIRD choice..here's why...
(p^2 – q^2)(p^2 + 3q^2) =
STEP ONE... multiply the two LEFT terms (p^2 x p^2)
= p^4
STEP TWO. multiply the two RIGHT terms (-q^2 x 3q^2)
= -3q^4
STEP THREE...Multiply the two END terms (p^2 x – 3q^2)
= -p^23q^2
Step FOUR... Multiply the two MIDDLE terms (q^2)(p^2)
= p^2q^2
STEP FIVE..ADD Steps 3 and Step 4
= 2p^2q^2
STEP SIX rewrite = p^4 + 2p^2q^2 – 3q^4 Hope this helped.

Answer 5

(p^2 – q^2)(p^2 + 3q^2)

multiply each term in one binomial by each term in the other

p^2p^2 + 3p^2q^2 - p^2q^2 - 3q^2q^2

p^4 + 2p^2q^2 - 3q^4

You can arrange the problem to look like a regular multiplication

p^2 - q^2
p^2 + 3q^2
- - - - - - - - - - - -
p^4 - p^2q^2
. . . +3p^2q^2 - 3q^4
- - - - - - - - - - - - - - -
p^4 + 2p^2q^2 - 3q^4

When multiplying like this, arrange like terms in the same column for easier adding

Answer 6

hey the answer should be p^4+2p^2q^2-3q^4

Answer 7

It is your third choice: p^4 + 2p^2q^2 - 3q^4

that's it! :)

Answer 8

Most say March, but I get better results planting them in November - providing I can protect them from severe ground frost.

Answer 9

Instead of posting yet another nearly-identical problem, learn how to multiply two binomials:
http://mathforum.org/library/drmath/view/53279.html

Answer 10

So what's your question? Am I supposed to just do your homework for you?