2007-12-19 07:09:13 · 3 answers · asked by Elestus V 2 in Science & Mathematics ➔ Physics
Fnet = T - Fg
ma = T - mg
1500(0.9) = T - (1500)(9.8)
T = 16050 N
Therefore the rope must be able to withstand at least 16050 N
2007-12-19 07:13:11 · answer #1 · answered by Jacob A 5 · 2⤊ 0⤋
The weight of the car = 1500 * g = 15 000 N (assuming g = 10ms-2), acting so as to stretch the rope
The accelerating force = 1500 * 0.9 = 1350 N, acting so as to stretch the rope
Tension in rope = 15000 + 1350 = 16 350 N
= 16.35 kN.
2007-12-19 07:37:00 · answer #2 · answered by sparky_dy 7 · 0⤊ 0⤋
The rope mus withstand the sum between the weight of the car mg and the force of inertia ma which shows downward becase the acceleration is upward
T=m(g+a)=1500(9.8+9)=28200 Newton
2007-12-19 08:05:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋