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2007-12-19 06:52:26 · 3 answers · asked by malkana d 2 in Science & Mathematics Mathematics

3 answers

6y^2 - 5y - 6 = 0

Using the quadratic formula, y = (5 +/- sqrt(25 + 144)) / 12 = (5 +/- 13) / 12 = -8/12 or 18/12 = -2/3 or 3/2. So the factors are multiples of (y + 2/3) and (y - 3/2), namely (3y + 2) and (2y - 3). The factorization is (3y + 2)(2y - 3).

2007-12-19 06:57:50 · answer #1 · answered by DavidK93 7 · 0 0

6y^2 - 5y - 6
(3y + 2)(2y - 3)

2007-12-19 14:56:49 · answer #2 · answered by miggitymaggz 5 · 0 0

(3y+2)(2y-3)

2007-12-19 14:57:02 · answer #3 · answered by ironduke8159 7 · 0 0

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