find the angles?

0 ⤊

PQR is parallel to BC and XC is a straight line. QCB [angle c]=62 degrees, XBC[angle B]=15degrees and BPQ[anglep]=110degrees
Calculate:
(i)RQC....[angleq]
(ii)PBX....[angle b]

2007-12-19 06:12:36 · 2 answers · asked by bubble 1 in Science & Mathematics ➔ Mathematics

2 answers

angle RQC = angle QCB = 62 degrees

angle PBX = angle PBC + angle XBC = 70+15 = 85 degrees
Note angle PBC = 180 -angle BPQ

2007-12-19 06:29:14 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

why the hell would u ask thats

2007-12-19 14:15:13 · answer #2 · answered by Andreu 2 · 0⤊ 0⤋