A 2.0-kg ball has a velocity of 15m/s downward just before it strikes the ground and bounces up with a velocity of 12m/s upward.
What is the change in momentum of the ball?
2007-12-19 06:09:21 · 2 answers · asked by xxtruflipxx 1 in Science & Mathematics ➔ Physics
Keep in mind momentum is a vector quantity. A change from 15m/s down to 12m/s up requires a change in velocity of 27m/s up, which corresponds to a momentum change of 2kg(27m/s)=54kgm/s
2007-12-19 07:28:58 · answer #1 · answered by supastremph 6 · 1⤊ 1⤋
p = mv
p is momentum, m is mass, v is velocity. The momentum when the ball is going downwards can be calculated by
p = 2kg x 15 m/s = 30
When its traveling up, it is
p = 2kg x 12 m/s = 24
the change in momentum is the final momentum - initial momentum, so
24 - 30 = -6. The change in momentum is -6.
2007-12-19 06:17:16 · answer #2 · answered by Sowmya 3 · 0⤊ 3⤋