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the internal dimensions of a saucepan shaped like a cylinder are height 20cm and diameter 35cm. Calculate to the nearest whole number,
(i)the area,of the bottom of the saucepan
(ii)the largest volume of liquid,in cm3,which the saucepan can hold.

2007-12-19 05:53:09 · 3 answers · asked by baby 1 in Science & Mathematics Mathematics

3 answers

A = 3.14*17.5^2 = 962 cm^2
V = 962*20 = 19,240 cm^3

2007-12-19 05:59:50 · answer #1 · answered by ironduke8159 7 · 1 1

For a circle:
A = r^2 * pi and r = 1/2d
d = 35cm so r = 17.5 cm
A = 17.5^2 * pi = 962 cm^2

Volume of a cylinder = A of base * h
V = Ab *h
V = 962cm^2 * 20cm = 19242 cm^3

Hope this helps! :)

2007-12-19 14:01:56 · answer #2 · answered by disposable_hero_too 6 · 0 0

Height =20cm
Diameter= 35 cm
Radius= 17.5 cm

Area of cylinde= 2(pie)(r^2) + (2)(pie)(r)(h)

(i)Area of the bottom of the saucepan= (pie)( 17.5^2)
= 962 cm^2

(ii) Volume= (pie)(r^2)(h)
= (pie)(17.5^2)(20)
= 19242 cm^3

2007-12-19 14:00:57 · answer #3 · answered by MG 2 · 1 0

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