A football is kicked with a speed of 18 m/s at an angle of 65 degrees to the horizontal.
a) How far does the football travel horizontally before it hits the ground?
b) What are the respective horizontal and vertical components of the initial velocity of the football?
2007-12-19 05:49:00 · 2 answers · asked by flipnv86@sbcglobal.net 1 in Science & Mathematics ➔ Physics
Figure out b) first.
Vh = Vo*cos(65)
Vv = Vo*sin(65)
a) Vvf = Vv + g*t
where Vvf is final vertical velocity, Vv is initial vertical velocity g = 9.8 m/s^2, and t is time to return to earth. When it returns to earth it will have the same vertical speed it started with, in the opposite direction. Vvf = -1*Vv. Solve for t.
Vh = x/t
where x is the distance it travels horizontally.
2007-12-19 07:12:33 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
they are Vx = horizontal component = 18 cos 65 and vertical component Vy = 18 sin 65 look into tables for the values of cos 65 and sin 65 and get your values. o. k
2016-05-25 01:27:47 · answer #2 · answered by myung 3 · 0⤊ 0⤋