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y^2+10y-20x+37=0

2007-12-19 05:41:10 · 2 answers · asked by Bashir B 1 in Science & Mathematics Mathematics

2 answers

Use the technique of completing the square to put the equation in the form (y + 5)^2 = 20(x - 3/5). Now you can easily recognize that the vertex is at (3/5,-5).

2007-12-19 09:15:03 · answer #1 · answered by Tony 7 · 0 0

take the derivative. set this equal to 0 and solve for y. and there is the answer

2007-12-19 05:48:26 · answer #2 · answered by Brent 3 · 0 0

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