Find the number of complex roots of x² -144=0?

Question

I already know I should have 2 roots because the exponent of x tells me that.

Answer 1

The roots are both real

x² - 144 = 0
x² = 144
x = 12 or x = (-12)

So if you want to write them as complex numbers I guess you could say
x = 12 + 0i
or
x = (-12) + 0i

Answer 2

x^2 - 144 = 0
x^2 = 144
x=+/-12

Both roots are real numbers. However, since all real numbers are part of the complex number system, you can also express this as

12+0i
-12+0i

Is that what you are looking for?

Answer 3

if it is x^2 - 144, there are no complex roots

x^2 - 144 = 0

x^2 = 144

x = 12 or -12

if the given equatuion is x^2 + 144 = 0

then it will have complex roots

x^2 + 144 = 0

x^2 = -144

x = 12i or -12i

Answer 4

x² -144=0
x² = 144
x = 12 and -12 (square roots are plus and minus)

You would have two real roots and no complex roots.

FYI: If the question was x² +144 = 0, then
x² = -144
x = 12i and -12i (i = the square root of -1)

and you wold have no real roots and two complex roots.

Answer 5

See sweetie it's got 1 complex root which is -12 and +12,in fact one complex root contains 2 numbers wich are only symmetric.

Answer 6

(x+12)(x-12) = 0
x = 12 or -12.
Both roots are real.