2007-12-19 04:29:44 · 7 answers · asked by HopefulMed S 1 in Science & Mathematics ➔ Mathematics
this is just a simple algebra problem. All you have to do is remember to keep like terms together. So basically first you have 5x-3x so you get 2x. That is just one part of your answer
I assume that its 5x - (5/(x^2)) - 9 and 3x -1/9 - x^2
since 9 and 1/9 are both numbers you can do that next. -9-1/9 = - 9 1/9
Finally you have a 5/x^2 and a - x^2 which aren't the same so you have to keep them thus you get
2x - 5/ x^2 +x^2 - 9 1/9
If that isn't how the problem was written just be sure to keep like terms together and unlike terms seperate.
2007-12-19 04:36:17 · answer #1 · answered by mblastguy 5 · 0⤊ 0⤋
= (5x-5)/(x^-9) + (3x+1)/(x^2-9)
= (8x-4)/(x^2-9)
=4(2x-1)/(x^2-9)
2007-12-19 12:36:30 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
I THINK its 2x^3 - 18x - 4 / x^2 - 9
2007-12-19 12:35:38 · answer #3 · answered by Anonymous · 0⤊ 1⤋
You need to rewrite the equation using parentheses, so it can be correctly solved.
2007-12-19 12:36:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋
4(2x-1)/(x+3)(x-3)
2007-12-19 12:37:33 · answer #5 · answered by pjpudge1414 2 · 0⤊ 0⤋
what are we meant to do with that.
it looks like it requires a bit of differentiation to do it
I've forgotten how that works
2007-12-19 12:32:47 · answer #6 · answered by jollyboy booboo 2 · 0⤊ 2⤋
get a calculator
2007-12-19 12:32:17 · answer #7 · answered by Anonymous · 0⤊ 2⤋