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A proton is accelerated from rest through a potential difference of 25700 V

a) whats the kinetic energy of this proton in joules after this acceleration?

b) whats the speed of the proton after this acceleration?
------------
ok once u find the E.P.E , which is E.P.E = V * q
but then what? AND WHY? IF Electrical Potential Energy= Kinetic Energy in this case , PLEASE EXPLAIN WHY.

2007-12-17 18:31:01 · 7 answers · asked by G3P 3 in Science & Mathematics Physics

7 answers

A proton is accelerated from rest.
Acceleration means change in velocity.
A proton is accelerated means its velocity changes from zero = [in this case] to some velocity.

Any particle having some speed is said to possess kinetic energy given by the formula
0.5mv^2. [Or Force x distance = m*a*s, where a is the acceleration and since it starts from rest. v^2 = 2as. Hence work or energy = m v^2/2]

The electrical potential energy vq implies a force is acting on the proton and hence it is accelerated and, the work done = force x distance moved = m v^2/2
Hence Vq = mv^2/2

2007-12-17 20:24:09 · answer #1 · answered by Pearlsawme 7 · 1 0

Electric Kinetic Energy

2016-11-08 00:15:32 · answer #2 · answered by ? 4 · 0 0

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Kinetic energy is energy due to motion and potential energy is energy due to position in a force field. The formula for translational kinetic energy is KE = 0.5*m*v^2, where m is mass and v is velocity. The most common type of potential energy is gravitational potential energy, and near the surface of the Earth (or some other planetary body) the formula is PE = mgh, where m is mass, g is acceleration due to gravity, and h is the height above the surface. Another common one is elastic potential energy in a compressed spring. In that case the formula is PE = 0.5*k*x^2, where k is the spring constant and x is the compression. An object can also have electrical potential energy, if it has an electrical charge and is positioned some distance from another charge.

2016-04-10 03:33:07 · answer #3 · answered by ? 4 · 0 0

The potential difference represents the energy difference; if the proton is restrained, it is potential energy. Allowing the proton to be accelerated converts the potential energy to kinetic energy. By the time the proton has passed through a potential change of V, is kinetic energy is qV and = 0.5*m*v^2, where v = speed of the proton and m = its mass.

2007-12-17 18:52:20 · answer #4 · answered by gp4rts 7 · 1 0

In such cases we apply the work-kinetic energy theorem i.e.
q(V(2)-V(1))=qU=muu/2 (1)
where q stands for the work done by the uniform electric field , V(2) and V(1) standing for the electric potential of the field at the final and initial position of the electric charge and U for the electric tension between the two points, muu/2 standing for the kinetic energy of the electron at the end of its acceleration process.
In what concerns the potential energy consider in order to simplify the problem that the charge of the involved particle qV represents the potential energy of the electric charge at the point where the electric potential is V.
From (1)
u=sqrt(2Uq/m) (2)
where q/m represents the specific charge of the proton expressed in As/kg.

2007-12-17 19:04:10 · answer #5 · answered by Anonymous · 0 1

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RE:
is Electrical Potential Energy= Kinetic Energy in this case?
A proton is accelerated from rest through a potential difference of 25700 V

a) whats the kinetic energy of this proton in joules after this acceleration?

b) whats the speed of the proton after this acceleration?
------------
ok once u find the E.P.E , which is E.P.E = V * q
but then what?...

2015-08-07 18:14:49 · answer #6 · answered by Anonymous · 0 0

Kinetic energy is the energy possessed by a body when in motion and is 0.5mv^2 whereby 0.5 is a constant, m is the mass of the body and v is the velocity of the body in the motion. Potential energy is the energy a body possess when in rest and is denoted by mgh whereby m is the mass of the body, g is the gravitational acceleration which is a constant (10ms^-2) and h is the height at which the body is from the ground surface.

2016-03-19 05:20:50 · answer #7 · answered by Jessica 4 · 0 0

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