The equation of the line in the figure below is y = __________?

Question

refer to:
http://img444.imageshack.us/my.php?image=20610535jc7.jpg

Answer 1

y = (1/2) x + 44.5

Solution: linear equation is y = mx + b

We have 2 given (x,y) coordinates, so we can easily solve for m and b:

47 = 5m + b
52 = 15m + b

From the first equation:
b = 47 - 5m

Substituting (47-5m) for b in the second equation:
52 = 15m + 47 - 5m

52 = 10m + 47

10m = 5

m = 5/10
m = 1/2

b = 47-5m = 47 - 5(0.5) = 47 - 2.5

b = 44.5

Answer 2

First find the slope of the line from the two points on the line.

m = ∆y/∆x = (52 - 47) / (15 - 5) = 5/10 = 1/2

Now write the equation of the line using the slope and one of the points.

y - 47 = (1/2)(x - 5)
y = (1/2)x - 5/2 + 47
y = (1/2)x + 89/2

Answer 3

the points are (15, 52)
and (5,47)
first find the slope wich is (52 - 47) / (15-5 )
which equals 5/10 = 1/2
pick a point ( it doesnt matter which one) and plug point into the equation y-y cordinate=m (x- x cordinate) m= slope
y-52=1/2 (x-15) OR y-47=1/2 (x-5)
i will use the first one.
distribute to get rid of the parenthesis
y-52=1/2x - 15/2
add 52 to both sides to get y=1/2x-(119/2)
or if you use the other equation you will get the equation
y=1/2x-(99/2)

Answer 4

Carson Z got the right formula, but he added when he should have subtracted. The answer is y=1/2 x + 89/2, for either point.

Answer 5

All you do is find the slope and where it crosses the x axis.

you will need a zero