Write expression in the form bi, where be is a real number
2√-162
A) -9i√2
B)-9√2
C) 9i√2
D) 9√2
2007-12-17 16:38:15 · 7 answers · asked by Ambiguous 1 in Science & Mathematics ➔ Mathematics
Hi,
2√-162=2√-(81*2)
______=2√((-2)(81))
______=2√(-2)√(81)
______=9·2√(-2)
______=9·2√2·2√-1
Note: √-1=i (imaginary base number)
______=9·2√2·i
check C) 9i√2.
luck,
2007-12-17 16:47:16 · answer #1 · answered by Anonymous · 1⤊ 1⤋
are ur answer choices right? cuz i believe 2â-162 should be 18iâ2
the square of 162 itself is 9â2
sq. roof of -1 becomes 'i'
and 9 times original 2 is 18
2007-12-18 00:46:38 · answer #2 · answered by jo 2 · 0⤊ 0⤋
It's C because â-1 is i
2007-12-18 00:45:02 · answer #3 · answered by Steph 1 · 0⤊ 0⤋
sqrt. -162= 9 sqrt -2
i=sqrt. -1
ans.= 9i sqrt.2
2007-12-18 02:10:53 · answer #4 · answered by i.heart.u 5 · 0⤊ 0⤋
sqrt((9^2)*2*(-1))= - 9i sqrt(2)
the sqrt(-1)=i
2007-12-18 00:44:40 · answer #5 · answered by shadowca1964 4 · 0⤊ 0⤋
x = â(-162)
x = â (162 i ² )
x = 9 i â2
OPTION C
2007-12-18 09:04:37 · answer #6 · answered by Como 7 · 3⤊ 0⤋
What's the question?
2007-12-18 00:45:17 · answer #7 · answered by scruffycat 7 · 0⤊ 0⤋