how on earth would i solve the area of an octagon if each side had a length of five?
pretty please show work with formulas or whatever.
thank you so much this means a lot!
2007-12-17 16:36:35 · 6 answers · asked by Answer 2 in Science & Mathematics ➔ Mathematics
ok, I'll help you...
area of an octagon when you know the length of the sides (d) is:
a = 2d^2(1+sqrt(2))
thus since d=5,
a= 2 x 5^2 x (1 + sqrt(2)) = 120.71
2007-12-17 17:02:59 · answer #1 · answered by micky9fingers 2 · 0⤊ 0⤋
draw a square around the octagon. you should have four triangles when done(one at each corner of the square). when you put those triangles together you get two more smaller squares. Find the area of the main square then subtract the area of the two smaller squares from the large one and that is the area of your octagon.
2007-12-17 16:58:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
hey there.
i got this answer off google but:
There is no simple equation to solve for the area of an octagon. To do this, you need to divide the octagon into triangular, square, and rectangular pieces.
there ya go.
2007-12-17 16:40:31 · answer #3 · answered by cecil 2 · 0⤊ 0⤋
hey the easiest way is to figure out the area ofone of the triangles and multiply it by 8
2016-05-24 11:19:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Break it up into eight triangles (the sides of each one will be one side of the octogon connected to the midpoint). Find the area of each triangle (I assume you know how to do that). Then multiply by 8.
2007-12-17 16:39:45 · answer #5 · answered by Ranto 7 · 1⤊ 0⤋
Check: http://en.wikipedia.org/wiki/Octagon#Regular_octagons
Formulas over there.
2007-12-17 16:41:47 · answer #6 · answered by ? 2 · 0⤊ 0⤋