frederiqu is two years older than her brother. twelve years ago she was twice as old as he was. how old are they now.
2007-12-17 16:10:58 · 6 answers · asked by chiyoung h 1 in Science & Mathematics ➔ Mathematics
call frederiqu's age x, so her brother's age is x-2. then it tells you that x-12=(x-2-12)*2, which simplifies to x-12=2x-28, then you get x=16, so she is 16 and her brother is 14.
2007-12-17 16:20:15 · answer #1 · answered by Nati F 3 · 0⤊ 0⤋
frederiqu = x
frederiqu brother = y
frederiqu is two years older than her brother
x = 2 + y
x - 12 = 2 (y -12 )
x - 12 = 2y -24
2 + y - 12 = 2y - 24
y = 14
x=2+14 = 16
They are frederiqu is 16 and her brother is 14
2007-12-18 00:22:00 · answer #2 · answered by Murtaza 6 · 0⤊ 0⤋
Let frederique be f years old
Brother is (f - 2) years old
12 years ago
Frederique was (f - 12) years .
Brother was (f - 14) years
f - 12 = 2(f - 14)
f - 12 = 2f - 28
f = 16 years
b = 14 years
2007-12-18 09:45:31 · answer #3 · answered by Como 7 · 3⤊ 0⤋
F = B+2; (F-12) = 2(B-12). B-10 = 2B-24; B = 14.
2007-12-18 00:16:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
f=2+b
f-12=2(b-12)
2+b-12=2b-24
b=14
f=16
frederiqu is 16 and brother is 14 years old
2007-12-18 00:16:32 · answer #5 · answered by someone else 7 · 0⤊ 0⤋
f= frederiqu
b= brother
f= b+2
f-12= b/2.
Solve.
2007-12-18 00:15:31 · answer #6 · answered by ? 2 · 1⤊ 1⤋