4x^2 – 36y^2
3x^2 – 2x – 8
24x^2 + 10x – 4
2007-12-17 16:00:19 · 6 answers · asked by Abena 2 in Science & Mathematics ➔ Mathematics
[10]
4x^2-36y^2
=4(x^2-9y^2)
=4{(x)^2-(3y)^2}
=4(x+3y)(x-3y)
3x^2-2x-8
=3x^2+4x-6x-8
=x(3x+4)-2(3x+4)
=(3x+4)(x-2)
24x^2+10x-4
=2(12x^2+5x-2)
=2(12x^2+8x-3x-2)
=2{4x(3x+2)-1(3x+2)}
=2(3x+2)(4x-1)
2007-12-17 16:12:19 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
4x^2 – 36y^2
= 4 ( x^2 - 9y^2) = 4 (x + 3y) (x - 3y)
(x^2 - 9y^2) is a difference of 2 squares.
3x^2 – 2x – 8
= (3x + 4)(x - 2) (trial and error, get factors of 8 and try them out one by one)
24x^2 + 10x – 4
Same trial and error approach:
(6x + 4)(4x - 1)
2007-12-17 16:23:07 · answer #2 · answered by jun m 2 · 0⤊ 0⤋
Greetings,
4(x^2 - 9y^2) = 4(x - 3y)(x + 3y)
3x^2 - 2x - 8
= 3x^2 - 6x + 4x - 8
= 3x(x - 2) + 4(x - 2)
= (3x + 4)(x - 2)
24x^2 + 10x - 4
= 2(12x^2 + 5x - 2)
= 2(12x^2 +8x - 3x - 2)
= 2(4x(3x + 2) - 1(3x + 2))
= 2(4x -1)(3x + 2)
Regards
2007-12-17 16:11:28 · answer #3 · answered by ubiquitous_phi 7 · 0⤊ 0⤋
4(x^2-9y^2)=4(x-3y)(x+3y)
(3x + 4 )( x - 2 )
2(12x^2+5x-2)=2(3x^2 + 2 )( 4x^2 - 1 )
2007-12-17 16:11:50 · answer #4 · answered by oldteacher 5 · 0⤊ 0⤋
4 (x^2- 9y^2)
(3x -4)(x+2)
2(12x^2 + 5x -2)
2007-12-17 16:04:00 · answer #5 · answered by mrr86 5 · 0⤊ 0⤋
adding to mrr86's response, the first one is also the difference of two squares
( 2x + 6y ) ( 2x - 6y )
2007-12-17 16:12:06 · answer #6 · answered by jgoulden 7 · 0⤊ 0⤋