Anybody know how to solve and what is the answer to the algebra problem?

0 ⤊

-x^0-x^2(x^0)^-3+4

x=-2
y=64

2007-12-17 15:33:35 · 2 answers · asked by Travis A 2 in Science & Mathematics ➔ Mathematics

-2^0- -2^2(-2^0)^-3 +4

-1+4(-1)+4=-1

-2^0=-1
-2^2=4
-2^0=1*-3=-1
4 SO
-1-4+4=-1

2007-12-17 21:08:30 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

-x^0=-1 since any number to 0 power is 1.
x^2(x^0)^-3= (-2)^2(1)^-3=4(1)^-3=4(1)=4
so, -1-(4)+4=-1

2007-12-17 23:43:23 · answer #2 · answered by oldteacher 5 · 0⤊ 0⤋