(-3x - 4)/-16 * 4x/(-x - 2)
2007-12-17 15:15:08 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(-3x^2 +4x)/[4(x+2)]
or
[x(-3x+4)]/[4(x+2)]
2007-12-17 15:20:08 · answer #1 · answered by Poetland 6 · 0⤊ 0⤋
I somehow got:
3x^3/ -4x^2-16x-16
I multiplied the denominators and numerators (=12x^2-16x/-16x-32), then I simplified by removing a 4 from each monomial (3x^2-4x/-4x-8), then I separated back out (3x^2/-4x-8 * -4x/-4x-8) Then I took out a -4 from the second fraction (3x^2/-4x-8 * x/x+2). Then I multiplied and foiled, getting the answer. I'm not sure if it's right, but at least I tried. I hope that helped. Merry Christmas, don't forget that Jesus is the reason for the season!!! ( :
2007-12-17 15:31:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I started by simplifying inside parentheses first!
-3x/-x =3 and -4/-2= 2 top is 3+2
bottom is 4x/-16....=x/-4
5 * x/-4
2007-12-17 15:32:55 · answer #3 · answered by raisedbycoyotes 5 · 0⤊ 0⤋
a negative divided by a negative is a positive. The signs cancel.
(3x+4*4x)/16(-x-2)
2007-12-17 15:37:55 · answer #4 · answered by Ed 3 · 0⤊ 0⤋
The only part that can be simplified is 4/-16 = -1/4. And you can distribute -1/-1 across the binomial factors in the numerator and denominator. That gives you -x(3x + 4) / (x + 2).
(3x + 4) isn't divisible by (x + 2), and (x + 2) isn't divisible by x, so there's nothing else you can do.
2007-12-17 15:17:28 · answer #5 · answered by DavidK93 7 · 6⤊ 1⤋
How about:
(3x + 4)(x) / (-4)(x + 2) ?
2007-12-17 15:22:06 · answer #6 · answered by Anonymous · 0⤊ 0⤋
(-- 3x -- 4) / (-- 16)*4x/(-- x -- 2)
= -- (3x + 4)*4x / 16(x + 2)
= --x(3x + 4)/4(x + 2)
2007-12-17 15:20:20 · answer #7 · answered by sv 7 · 0⤊ 0⤋
(-3x - 4)/-16 * 4x/(-x - 2)
=(-3x - 4)/-4 * x/(-x - 2)
2007-12-17 15:17:36 · answer #8 · answered by DANIEL G 6 · 1⤊ 1⤋
-(3x+4)x/4(x+2)
2007-12-17 15:18:44 · answer #9 · answered by someone else 7 · 1⤊ 1⤋
x(-3x-4)/(4x+8)
2007-12-17 15:20:08 · answer #10 · answered by swimmer12_9 2 · 0⤊ 0⤋