Analytical trigonometry?

Question

Sinx-Sin^2 / cos^2x
I have no idea.
Can someone show me how to work it out?

Answer 1

=(sin- sin^2x)/cos^2x
=sinx(1-sinx)/ ( 1-sin^2x) since cos^2x= 1-sin^2x
=sinx(1-sinx)/ ( 1-sinx)(1+sinx)
=sinx/(1+sinx)

Answer 2

First, rewrite your numerator as sinX(1-sinX). This is simple factoring.

Second, rewrite your denominator as 1-sin^2X, then rewrite it again as (1-sinX)(1+sinX). Here, you used Pythagoras's theorem first, then factored it.

Now, you can cancel 1-sinX from both sides, and what you have left is sinX/(1+sinX)

You can not go any further than this.