from a table of all five-digit numbers. What is the probablity that the number is evenly divisible by 1, 2, 3, 4, and 5?
2007-12-17 12:29:58 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1- 100%
2-50%
3-33%
4-25%
5-20%
2007-12-17 12:33:45 · answer #1 · answered by Anne 2 · 2⤊ 0⤋
All are divisible by 1.
Exactly half are divisible by 2.
10000 is 1 mod 3. 99999 is 0 mod 3, so exactly 1/3 are divisible by 3.
10000 is 0 mod 4. 99999 is 3 mod 4, so exactly 1/4 are divisible by 4.
10000 is 0 mod 5. 99999 is 4 mod 5, so exactly 1/5 are divisible by 5.
A number that is divisible by 1, 2, 3, 4, and 5 is divisible by 60. 10000 is 40 mod 60. 99999 is 39 mod 60. So exactly 1/60 are divisible by all of 1, 2, 3, 4, and 5.
2007-12-17 20:49:37 · answer #2 · answered by jaz_will 5 · 1⤊ 0⤋
There are 89999 possible numbers. To be evenly divisible by all those numbers at the same time, the number must be divisible by 120. So there are exactly 799 such possible numbers between 10,000 and 99,999. The chances of chosing a random one from the available 89,999 numbers is 0.888%.
Right: Jaz is right. I messed up.
2007-12-17 20:49:25 · answer #3 · answered by Zelda Hunter 7 · 1⤊ 0⤋
1- 100%
2- 50%
Not sure for the others. Idk if I understand the question, could you reword and I'll edit and give you the correct answer?
2007-12-17 20:33:38 · answer #4 · answered by Anonymous · 0⤊ 0⤋
25????? 30 50?????
2007-12-17 20:33:03 · answer #5 · answered by bella 2 · 0⤊ 0⤋
12,435
am i right
2007-12-17 20:33:00 · answer #6 · answered by Rebekah A 1 · 0⤊ 0⤋
who cares?
2007-12-17 20:32:30 · answer #7 · answered by Anonymous · 0⤊ 1⤋
12,345!
Am I right?
2007-12-17 20:32:43 · answer #8 · answered by Anonymous · 0⤊ 1⤋
there is no limit.
2007-12-17 20:32:42 · answer #9 · answered by Anonymous · 0⤊ 0⤋