log ( 4x+1 / 2x+9) = 0
2007-12-17 11:56:56 · 4 answers · asked by chriskel8706 1 in Science & Mathematics ➔ Mathematics
log ( 4x+1 / 2x+9) = 0 (can't see the base 10)
This is really 10^0 = 4x+1 / 2x+9
1 = 4x+1/2x+9
2x+9 = 4x+1
8=2x
x=4
2007-12-17 12:00:55 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
By definiton, (4x+1)/(2x+9)=1
(4x+1)=(2x+9)
2x=8
x=4
2007-12-17 12:02:25 · answer #2 · answered by cidyah 7 · 0⤊ 0⤋
All answer are incorrect or in part suitable! The is a attempt no count if the equation holds. as a results of fact the quotient x/x is given, the equation is defined for x=0, as a results of fact the certainty, that there is a real shrink for x goint to 0 of x/x: limit_x->0 x/x=a million. So do away with the quotient a minimum of for x unequal 0. The equation now could be x+x²=x². This equation could properly be rearranged through unique arithmetic operations. It supplies x=0. stupid or. What does is mean? The equation would not carry for x unequal 0. that's it. it could returned be simplified a million+x=x or a million=0, that's inaccurate. For 0 is holds interior the secure type and interior the shrink attention: 0/0+0=a million+0 unequal 0. The equation would not be valid for any authentic numbers!
2016-12-11 08:07:18 · answer #3 · answered by ? 4 · 0⤊ 0⤋
10^0 = 4x + 1/2x +9
logb a = y == b^y = a
Now just solve for x.
2007-12-17 12:02:50 · answer #4 · answered by Daniel B 2 · 0⤊ 0⤋