verifying trig terms?

(sinx+cosx)^2-1=sin2x

2007-12-17 11:02:37 · 1 answers · asked by Someone E 1 in Science & Mathematics ➔ Mathematics

1 answers

Left hand side (LHS):
=(sinx+cosx)^2-1
=(sinx+cosx)(sinx+cosx) -1
=sin^2x + 2sinxcosx +cos^2x -1 (note: sin^2x + cos^2x = 1)
=sin^2x + cos^2x +2sinxcosx -1
= 1 +2sinxcosx -1 (note: 2sinxcosx= sin2x)
=sin2x = RHS

2007-12-17 11:07:09 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 1⤊ 0⤋

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