What are the values of x and y???

Question

Please help me find the values of x and y.

(3x-11y)=47
(x+y+7)= 54

Answer 1

There are a number of ways to find this. You could use combination (or elimination), substitution, graphing... I'll use substitution because it's the simplest to teach.

3x - 11y = 47
x + y + 7 = 54
x + y = 47

First, you need to isolate one of the variables (either x or y) in ONE of the equations. Since the second has both variables without coefficients, it doesn't really matter which one you isolate completely. I would isolate y because it's more familiar.

y = -x + 47
3x - 11y = 47

Now that you know that y = -x + 47, you can plug that in for y in the second equation.

3x + 11(-x + 47) = 47
3x - 11x + 517 = 47
-8x = -470
x = 58.75

Now that you know the value of x, you can plug 58.75 for x in one of the original equations.

3(58.75) - 11y = 47
176.25 - 11y = 47
- 11y = -129.25
y = 11.75

So your answer is (58.75, 11.75). To check that your answer is correct, plug both variables into the original equations.

Hope this helped!

Answer 2

Take the second equation, and move the seven to the other side:
x+y=54-7=47
So, you can therefore say x=47-y by moving the y over as well.
Substitute this into the first equation:
3(47-y)-11y=47
141-3y-11y=47
14y=94
y=94/14=47/7
Now, you said x=47-y,
so x=47-47/7
With a common denominator of 7:
(329-47)/7=282/47=6

So, (x,y)=(6,47/7)

Answer 3

from x+y+7=54. x=47-y
3(47-y)-11y=47
-12y=-94
y=47/6

plugging back in
x=235/6

Answer 4

3x-11y=47
x+y=47

3x-11y=47
- 3x+3y=141
14y=94
y=6.7142857

x+y=47
x+6.7142857=47
x=40.2857

Answer 5

i simply said that x + y +47 so y = 47-x, then plugged that into the other equation, solved for x and got x = 40.29, and y= 6.71

Answer 6

3x-11y=47
x+y+7=54

3x-11y=47
x=47-y

3(47-y)-11y=47
141-3y-11y=47
-14y=-94
-14y/-14=-94/-14
y=6.71428

x+y=47
x=40.28572