Two rules to use: ln(a/b) = ln(a) - ln(b), and ln(x^a) = a*ln(x).
So we break up your problem first into ln(1) - ln(25). ln(1) = 0, so we're left with -ln(25). Now 25 = 5^2. So -ln(25) = -ln(5^2) = -2*ln(5).
Then just use what you were given.
2007-12-17 09:33:19
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answer #1
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answered by mathlete 2
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The above answers are all correct given that ln 5 = 1.099. However, in reality, ln 5 â 1.609, not 1.099. This is the reason why they don't agree with what you're getting on your calculator (at least I assume that's why you're giving them all thumbs down).
2007-12-17 17:56:36
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answer #2
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answered by Pascal 7
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ln (1/25) = ln 5^-2 = - 2 ln 5 = 2(1.099) = -2.198 = ~-2.20
that's it! :)
2007-12-17 17:28:08
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answer #3
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answered by Marley K 7
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In general, ln(x^y) = y*ln(x)
ln(5) = 1.609437912 not 1.099
ln(5^-2) = -2*ln(5) = -2.198
2007-12-17 17:27:54
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answer #4
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answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6
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ln[1/25]=-2ln5=-2*1.099=-2.198=-2.20approx.
2007-12-17 17:28:59
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answer #5
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answered by Anonymous
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ln(1/25)=ln5^-2=-2ln5=-2(1.099)=-2.20
2007-12-17 17:30:13
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answer #6
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answered by someone else 7
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