helppp with angular acceleration. pleaseee?

Question

A beam has an angular velocity of 10 rad/s. After 40 revolutions its angular velocity has increased to 30 rad/s. Find angular acceleration. If the beam has a mass of 10 kg and a force of 10N acting on it. Find F1 which is located at the end of the 5 meter beam.

**I'm not sure if you have to convert rad/s to rev/s?

Answer 1

1 revolution = 2*pi radians

40 revs = 80*pi radians

So q = (w1^2-w0^2)/(2 a) q = angular displacement, w1 and w0 final and initial angular speeds repsectively, and a = angular acceleration

a = (w1^2-w0^2)/(2q) = (30^2-10^2)/(2*80*pi) =5/pi radians/sec^2

Not sure what you are looking for in last part.