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given the following information:
1) I used 9.586g of steel
2) The specific heat for the steel is 0.447 joules/g deg. C
3) I put the steel in 65 ml of water
4) the temperature of the water started at 22 deg C and ended at 41 deg C
5) the only equation that I have is calorie= mass X change in temperature X (cal/ g degrees C)
6) 4.18 joules = one calorie.

2007-12-17 08:18:00 · 1 answers · asked by Luke H. 1 in Science & Mathematics Chemistry

1 answers

For methane (natural gas)
Maximum burning temperature: 2148 °C
Melting pointof Iron 1811 K (1538 °C, 2800 °F)
The melting point of any steel cannot exceed the melting point of iron, which is far below the flame temperature of methane.
Given the data you supplied and solving for the original temperature of the steel,
(9.586)(0.447)(T - 41) = (65)(4.18)(41 - 22)
T = 41 + (65)(4.18)(41 - 22) / (9.586)(0.447)
T ≈ 1,245 °C

2007-12-18 03:46:28 · answer #1 · answered by Helmut 7 · 0 0

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