What is the center and radius of the circle with equation (x-2)^2 + (y-5)^2=100?

Answer 1

The equation is in a form where you can read the center directly from the equation:
(2, 5)

In general, if you have:
(x - a)² + (x - b)² = r²

Then the center is (a, b) and the radius is r. You didn't ask, but the radius of your circle would be 10.

Answer 2

The center of the circle can be found by looking at x - 2 and y - 5 and setting them equal to 0.

x - 2 = 0
x = 2

y - 5 = 0
y = 5

Therefore the center of the circle is (2, 5)

The equation is in the form x^2 + y^2 = r^2
This means that 100 = r^2
r can either be positive or negative 10.

In this case, the radius must be positive 10, as lengths are positive numbers.

Answer 3

The center of the circle is (2,5) and the radius is 10.

It is of the form (x-h)^2 + (y-k)^2 = r^2.

Answer 4

you find these by looking at the equation yes.

the co-ordinates are the opposite of the numbers inside the paranthesis yes so you have

(2,5) as the center

and the radius is squared yes

so the radius is 10 in this equation.

Answer 5

center is (2,5) and radius is 10

general equation of circle is (x-c1)^2 + (y-c2)^2=r^2

where (c1, c2) is the centre and r is the radius