after coming down a hill with a 35 degree slope, the sled with a mass of 35 kg, coasts up a long hill with a 30 degree slope that has a coefficent of friction of 0.083. How far up the second hill does the sledder go?
2007-12-17 07:36:35 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
oh my bad .. the first hill was 35 kg.
2007-12-17 07:42:46 · update #1
it had friction .. 0.083
2007-12-17 07:48:38 · update #2
How high was the first hill? Had it had no friction?
Let first hill be height h1 then
Pe1= mgh1
then
Pe1= Pe2 - Wf
Pe2= mgh2
Wf2= u mg cos(30) S2 where S2= h2/sin(30)
finally
mgh1=mgh2- u mg cos(30) h2 / sin(30)
h1=h2[1 - u cotan(30) ]
h2= h1/(1-u cotan(30)]
so what was the height of th efirst hill?
is the first hill had friction then
Pe1 - Wf1= Pe2-Wf2
Wf1= u mg cos(35) S1 where S1= h1/sin(35)
2007-12-17 07:41:38 · answer #1 · answered by Edward 7 · 1⤊ 1⤋
ew, i hate physics:S
i'm amazing at everything else
except for that.
2007-12-17 15:52:34 · answer #2 · answered by Wanderlust. 4 · 0⤊ 1⤋