ok i have another one for you guys <3?

Question

a 75 kg man is on a surface that has a coefficent of kinetic friction with his shoe soles of .15 and a static coefficent of 0.2. A 50 kg woman is on a surface that has a coefficent of kinetic friction with her shoe soles of 0.25 and a static coefficent of 0.35. If they have a tug a war, (a) who will be the first to move and (b) what will the acceleration be if the stationary person maintains as much tension in the rope as possible without slipping?

Answer 1

fs(man)= us1m1g= 147N
fs(woman)= us2m2g=172 N

The man will slide.....

fd(man)= ud1m1g= 110 N
fd(woman)= ud2m2g=123 N

The woman remains stationary as the man will slide with with an acceleration a
a=(F2-F1)/m1=(172-110)/75=0.83 m/s^2