A rocket sled is propelled by a solid propellant rocket motor of 6.027×10^5 N thrust. If the sled travels 1.776×10^3 m while attaining a top speed of 8.240×10^2 m/s.
i found the acceleration = 1.912×10^2 m/s^2
but what is the mass of the rocket sled?????
2007-12-17 03:45:37 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
the computer says that 2999.9kg is wrong i dont know if i have to convert it or not.
2007-12-17 03:54:08 · update #1
Lets find acceleration
V²=2as²+U²
(8.240x10²)²=2(a)(1.776x10^3)+(0)²
a=191.1531532 m/s²
F=ma
Driving force = ma
6.027x10^5 = m(191.1531532)
m=3152.961976 Kg
2007-12-17 03:52:40 · answer #1 · answered by Murtaza 6 · 0⤊ 0⤋
The description as a rocket "sled" indicates the motion is purely horizontal.
Neglecting friction, there is a constant acceleration produced by the constant force ( thrust ).
V= final velocity ; a = acceleration; F = thrust ; D = distance traveled
V^2 = 2 a D; a = V^2/ (2D) =[67.90X10^4 m^2/s^2]/2X1.776X10^3 a a = 1.912X10^2 m/s^2
F = m a ; m = F/a = (6.027X10^5)/(1.912X10^2) Ns^2/m = 3.152X10^3 Kg
2007-12-17 04:27:28 · answer #2 · answered by LucaPacioli1492 7 · 0⤊ 0⤋
If you know the acceleration and the force causing it then you can get the mass from Newton's 2nd law.
Why do you mention friction at the start of your question? It would seem you can neglect that for this problem.
2007-12-17 03:50:06 · answer #3 · answered by Steve H 5 · 0⤊ 0⤋