2007-12-17 02:04:04 · 11 answers · asked by sneha 2 in Science & Mathematics ➔ Mathematics
yes
2007-12-17 02:11:09 · answer #1 · answered by scruffycat 7 · 0⤊ 0⤋
X > -5
2007-12-17 02:14:23 · answer #2 · answered by Kaaks 3 · 0⤊ 0⤋
If you have 5 - x < 0, then add x to both sides, and you'll get
5 < x.
In the second equation, you have 5 + x > 0. Subtract 5 from both sides, and get x > -5.
You need both to be true, so 5 < x.
2007-12-17 02:10:39 · answer #3 · answered by mathlete 2 · 0⤊ 0⤋
1)5-x<0 ==> 5
1,2 ==>x>5
2007-12-17 02:09:04 · answer #4 · answered by MKA 2 · 0⤊ 0⤋
y= 5/3 and x= 0 or (0.5/3) to apply removing, the precise equation could be prolonged by potential of -2. After including them at the same time, that leaves you with y= 5/3. in case you place it into any of the two given equations you get 0 for x.
2016-11-28 00:16:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋
All you need to do is treat the inequality as an equation.
5-x>0
-x>-5
x<5
5+x>0
x>-5
2007-12-17 02:10:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋
5- x < 0 add x to get 5 < x or x > 5
5+ x > 0 subtract 5 from both sides x > - 5
for both to be true x > 5(if you wanted that way)
2007-12-17 02:10:30 · answer #7 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
(5-x)<0
(5-6)<0
-1<0
and
(5+x)>0
(5+6)>0
11>0
So the answer is x=>6
2007-12-17 02:12:53 · answer #8 · answered by Anonymous · 0⤊ 0⤋
if (5-x)<0 then solution is x>5
if (5+x)>0 then solution is x must be less than 5
2007-12-17 02:11:10 · answer #9 · answered by narayana rao 2 · 0⤊ 0⤋
5 - x < 0
- x < - 5
x > 5
5 + x > 0
x > -5
5 < x > - 5
x > 5
Also its an inequality, not an equation.
2007-12-17 02:10:07 · answer #10 · answered by James B 2 · 0⤊ 0⤋
the 2 inequalities say x> 5 and x>-5
hence intersection is x > 5
2007-12-17 02:09:20 · answer #11 · answered by ashphim 2 · 0⤊ 0⤋