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Calculate the pH of a solution with 6gpl sulfuric acid?

2007-12-16 22:54:19 · 1 answers · asked by St Lusakan 3 in Science & Mathematics ➔ Chemistry

1 answers

6gpl= 6/98 molar= 6*2/98 normal

pH=log(1/normality of solution)

pH=log[1/(6*2/98)]

pH=log(98/12)

solve this and get your answer

2007-12-19 19:08:49 · answer #1 · answered by Anonymous · 0⤊ 0⤋

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