(1 pt) Find the derivative of y = 10 t^6 − 3 √t + [9/t]?

0 ⤊

y = 10 t^6 − 3 √t + [9/t]

2007-12-16 16:51:24 · 3 answers · asked by rivergirl 1 in Science & Mathematics ➔ Mathematics

y = 10t^6 - 3t ^1/2 + 9(t^ -1)
y ' = 60t^5 - [ (3/2)(t^ -1/2)] - 9(t^ - 2)
y ' = 60t^5 - [(3/2)(t^ - 1/2)] - (9/ t^2)

2007-12-16 17:13:14 · answer #1 · answered by LE THANH TAM 5 · 0⤊ 0⤋

y = 10 t^6 − 3 √t + [9/t]
y = 10 t^(6) - 3 t^(1/2) + 9t^(-1)
y' = 60 t^(5) - (3/2) t (-1/2) - 9t^(-2)

2007-12-16 16:59:23 · answer #2 · answered by jgoulden 7 · 0⤊ 0⤋

with respect to t

60t^5-(3/2(t^1/2))-(9/t^2)

2007-12-16 16:57:35 · answer #3 · answered by golffan137 3 · 0⤊ 0⤋