Can Anyone explain to me this (Applied Discrete Math): p->r p->q = p->(r^q)?

Question

How do you solve this?

Answer 1

The two statements on the left should be anded together.

Once you do that, write out a truth table -- or at least part of one -- and you'll be fine.

In case of doubt, just write out a truth table, or part.

In this problem, for example, all the parts with p being false are pretty much the same, whatever q and r are.

Ditto anything with q false or r false.

And that doesn't leave much remaining. :)

Answer 2

You seem to be missing an operator between r and p on the left hand side.