Distance between two points?

Question

The distance between two points is 7, the points are (5, 2) and (x, 4); what is x?

Answer 1

7 ² = (x - 5) ² + (4 - 2) ²
49 = (x - 5) ² + 4
(x - 5) ² = 45
x - 5 = ± 3√5
x = 5 ± 3√5

Answer 2

3

Answer 3

The Euclidean distance is the square root of (5-x)*(5-x)+(2-4)*(2-4), or that of 25-10*x+x*x+4,

equate this square to the square of 7, collect the like terms, which gives:

x*x-10*x-20=0

That will give you 2 values hence 2 points on the line y=4.

I get x=5+/-sqrt(180)/2.

Answer 4

JP L - This looks like an imperative, even inspite of the undeniable fact that it can't be! what's going to you combine, and why? right here the quantity in question is distance, which dpends on discrete factors, not a continuos area! Jerome - the factor of rotation ameliorations. additionally, the quantity of rotation is an AP. it is unquestionably not a ray sweeping a circle. How did you get to this end? If Jerome is sweet, please clarify! If he's not, perhaps using complicated factors as a rotating arrow in a airplane could be effective. The LHS of the equaion could have words like a1 - a2, a2-a3 and such so as that on addition, each intermediate term would be cancelled off and we could get a1 - a182. If teh RHS can then be simplified and evaluated, you're able to get your answer.

Answer 5

x =9

Answer 6

7=sqrrt(4-2)^2+(x-5)^2
49=4+X^2-10X+25
X^2-10X-20=0
X=10+-SQRT100+80 ALL OVER 2
x=10+-sqrt180 all over 2
x=5+-3sqrt5

Answer 7

x would around 8, 9, or 10 but im not completely sure

Answer 8

idk about all the other answers but im thinkin -3. but idk.