equation: 3x-y=0?

Question

eqn: 3x-y=0
which way will the line be? i mean positive direction or negative direction?..
so..is it towards the right or left? i know it pases through (0,0)

Answer 1

set it in y=mx+b form

3x-y=0
-y=-3x
y=3x
positive slope

Answer 2

change the formula into slope intercept form (y=m(x-a))
which is y=3x then y=3(x-0) therefore the slope is 3
from (0,0) go up three places in the y direction and over 1 in the x direction and you have the next point follow this procedure and draw a line through the points and there is your line or make a litte table

x 3x y
-3 3(-3) -9
-2 3(-2) -6
-1 3(-1) -3
0 3(0) 0
1 3(1) 3
ect

Answer 3

Best way to analyse a line is to rewrite the equation in standard line format:

y = mx + c
where m is the slope (how fast does y increase when x increases by 1 unit), and
c is the intercept (the value of y when x = 0).

Here:
y = 3x + 0

c = 0, the line passes through (0, 0)
m = +3, the line increases (up, positive) very rapidly as you move to the right (as x increases).

Answer 4

To put it simply, the line moves from (-,-) to (+,+). Bottom left to the top right.