Physics tension + friction Problem?

Question

four climbers have tied themselves together with rope.
They march uphill (20 degrees) with an accel of 1.3 m/s2.
The three climbers behind the leader don't climb at all dragging with a coefficient of .11. the leader does all the climbing.
Find the tension between each rope and the force that that leader applies if their weights are as follows.
Leader 6kg
next 2kg
next 12kg
last 4kg

I dont even know where to start. help me please?

Answer 1

Very light, must be dogs

look at a FBD of the leader
F is the force he exerts on the ground to put tension in the rope
F-T1=6*1.3
next
T1-T2-2*9.81*0.11=2*1.3
next
T2-T3-12*9.81*0.11=12*1.3
last
T3-4*9.81*0.11=4*1.3

T3=9.51 N
T2=38 N
T1=42.8 N
F=50.6 N

j

Answer 2

I don´t communicate excellent english. interior the accelaration i've got been given -2.3543, my equations have been: -friction(a million)- rigidity = m * a (a million) -friction(2)+ rigidity = m * a (2) upload equation (a million) and (2) to do away with rigidity: -friction(a million)- friction(2)= (m1 + m2) * a sparkling up for a: -(uk*m1*gravity) -(uk*m2*gravity) / (mass1 + mass2) = a