Solve. 6x^2+7x=3?

Answer 1

6 x ² + 7 x - 3 = 0
x = [ - 7± √(49 + 72) ] /12
x = [ - 7 ± √(121) ] /12
x = [ - 7 ± 11 ] /12
x = 4 / 12 , x = - 18 / 12
x = 1 / 3 , x = - 3 / 2

Answer 2

Since x is to the power of , this is a quadratic equation. Move everything to the left side:

6x^2 + 7x - 3 = 0

Now, use factoring or quadratic formula (discriminant) to solve.

I will use discriminant (D).
D = b^2 - 4ac = 49 - 4(6)(-3) = 49 + 72 = 121

x1 = [-b - sqrt(D)] / 2a = (-7 - 11) / 12 = -18 / 12 = -3/2
x2 = [-b + sqrt(D)] / 2a = (-7 + 11) / 12 = 4 / 12 = 1/3

he general form of quadratic equation is:
ax^2 + bx + c = 0,
so now you see that:
a = 6, b = 7, c = -3

Hope that helps

Answer 3

First find out the 2 factors

6x^2 + 7x = 3
6x^2 + 7x - 3 = 0
6x^2 + 9x - 2x -3 = 0
3x(2x + 3) - 1(2x + 3) = 0
(3x - 1) (2x+3) = 0

Then solve for x

3x - 1 = 0
3x = 1
x = 1/3

2x + 3 =0
2x = -3
x = -3/2

Check to make sure they work

x = 1/3 x = -3/2

Answer 4

3/43