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the return trip against the same current took 4 hours. find the speed of the boat in still water

2007-12-16 13:26:43 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Distance = Rate x Time

Let S be the speed of the boat in still water and C be the speed of the current.

Leg 1: D = ( S + C ) ( 2 hours )
Leg 2: D = ( S - C ) ( 4 hours )

Set them equal:

( S + C ) ( 2 hours ) = ( S - C ) ( 4 hours )

Plug in 5 mph for C and solve for S in mph.

2007-12-16 13:32:10 · answer #1 · answered by jgoulden 7 · 0 0

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