2007-12-16 13:04:06 · 4 answers · asked by lizerbeth28 2 in Science & Mathematics ➔ Physics
The energy of a photon is
E = hf = hc / λ
where h is Planck's Constant, f the frequency, λ the wavelength, and c the speed of light.
Therefore, the photon with the larger wavelength ( orange ) will have the smaller energy.
2007-12-16 13:08:48 · answer #1 · answered by jgoulden 7 · 3⤊ 0⤋
The energy of a photon is given by the equation E = hf, where E is energy, h stands for Plank's Constant, and f represents frequency.
Also, c = f λ, and therefore f = c/λ
now E = h (c/λ)
h is a constant, and not crucial to solve problem.
so from the equation, you can see that the larger the wavelength (λ), the lower the energy. Therefore, a blue photon has more energy than an orange photon because it has a smaller wavelength.
2007-12-16 21:11:53 · answer #2 · answered by Bernard 4 · 1⤊ 0⤋
A Photon with less wavelength has more energy.
according to the equation E=hc/w.
where w is wavelength of light.
therefour blue (480nm) has more energy.
2007-12-18 01:36:47 · answer #3 · answered by Joshua 2 · 0⤊ 0⤋
http://ledmuseum.home.att.net/ledvio.htm
www.google.com
you can't go wrong.
2007-12-16 21:14:58 · answer #4 · answered by Fran 3 · 0⤊ 0⤋