An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck to the wall and does not slide down when the floor drops away.
The acceleration due to gravity is 9.8 m/s/s.
Given g = 9.8 m/s/s, the coefficient u=0.444 of static friction between a person and the wall, and the radius of the cylinder R = 3.7 m. For simplicity, neglect the person's depth and assume he or she is just a physical point on the wall. The person's speed is
v= (2 Pi r)/ T
where T is the rotation period of the cylinder
Find the maximum rotation period T of the cylinder which would prevent a 65 kg person from falling down. Answer in units of s.
2007-12-16
12:48:57
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics