I work for a company in MA. We only have one floating holiday which we all work inorder to have the day after thanksgiving off. BUT the company is CLOSED christmas eve and new years eve and they require us to either that a vacation day or unpaid is this legal? Its not my fault they are not open.
2007-12-16 12:08:01 · 6 answers · asked by JMBELLS 2 in Business & Finance ➔ Careers & Employment ➔ Law & Legal
I want to point out that they company only pays us for Christmas Day and New Years Day. Not the Eves that they are closed.
2007-12-16 12:46:49 · update #1
Sure it's legal. In fact, it would be legal if they didn't pay you for Christmas or New Years day either. Companies are not required to give you paid holidays.
It's not a matter of fault. You aren't working, so they don't have to pay you.
2007-12-16 16:06:55 · answer #1 · answered by Judy 7 · 0⤊ 0⤋
It's legal and very common practice for companies that close over the Christmas holidays.
2007-12-17 11:24:40 · answer #2 · answered by leysarob 5 · 0⤊ 0⤋
Yes they can my company i work for does not pay for Eve's or day after Thanksgiving they put that in the employee hand book that you get when you are hired.Good luck
2007-12-16 23:27:59 · answer #3 · answered by wanna know 6 · 0⤊ 0⤋
Vacation and holiday pay are BENEFITS, not something that they are required to pay. They are getting no additional income on those days to pay the salaries of those who are not working.
Why should they have to pay you to have a holiday. True, they are closed - most employees want that time off, and one day on one day off is difficult and has additional costs.
2007-12-16 23:46:16 · answer #4 · answered by mj69catz 6 · 0⤊ 0⤋
Of course it is legal. They are not obligated to pay you for a day you don't work when they are not open. Why should they be?
2007-12-16 20:15:50 · answer #5 · answered by theseeker4 5 · 1⤊ 0⤋
It is not illegal. You don't get paid when you don't work. It is their option to remain closed on those days and not pay you.
2007-12-16 21:58:12 · answer #6 · answered by acermill 7 · 1⤊ 0⤋