can anybody help me out by getting a factor tree for the number 17710 started??

Question

i just need help STARTiNG...so maybe just like the first 2 steps

Answer 1

split it into 1771 and 10, 10 into 2 and 5. try 1771/3, doesn't work. obviously don't try 5. try 1771/7, get 253, so split 1771 into 7 and 253. you know 2,3,5 don't work, so try 253/7, no, try 253/11, get 23, so 253 splits into 11 and 23, and you're done.

Answer 2

First thing I'd do is divide by 10. (gives you the prime factors 2 and 5). Now... 1771: harder to factor. But - because 3 and 7 are the only prime numbers that have multiples that end with one (3 x 7 = 21), they're worth trying. 1771/7 = 253, so 7 is a factor. 1771/3 gives a fraction, so what you wanted was 7, not 3. 253 is divisible by umm.... a little trial and error says 11. Another prime. And.. it turns out that 23 is also a prime number, so you can't factor it any further.

So... 17710 = 5 x 2 x 7 x 11 x 23.

That didn't take any math magic... just trying some possibilities, and finding what worked. Odds are you won't see an identical question on a test - but hopefully the method makes enough sense that you could do it with any number.

Answer 3

start at the bottom 2 x 8855, then 8855 comes out to 5 x 1771, 1771is 7 x 253, then 253 is 11 x 23. then 2 x 5x 7 x 11 x 23 equals 17710 good luck

Answer 4

177

these are the factors of 1771...
7 11 23 10
7 11 and 23 are prime. 10 is 2X5

17710
/ | | \
7 11 23 10
/ \
2 5

Answer 5

17710 / 70 = 253
(factor 70 = 7 x 5 x 2)
253 / 23 = 11

so...

11 x 23 x 7 x 5 x 2 = 17710

Answer 6

How about starting with 10.

17710

(10 -- 1771)

(2 -- 5) (7 -- 253)

Answer 7

2 * 5 * 7 * 11 * 23

Answer 8

divide 2 then divide 5

Answer 9

17710
^
5 x 3542
^
7 x 506

hope this is a good start :)
good luck

Answer 10

divide it by 2

then by five

and go from there