write an equation in standard form of the line that passes through the points (0,-7) and (-7,0)?

Answer 1

m = (0 + 7) / (- 7 - 0)
m = - 1

y - 0 = (-1) (x + 7)
y = - x - 7

Answer 2

This problem is called the 2-point form... since two points are given,
The equation of the line is y = mx + b
where m is the slope
and b is the y-intercept

given two points the equation can be solved by
1. computing the slope, m
2. substituting the slope to the equation of the line using any of the two points to find the y-intercept, b

Given,
P1=(0,-7)
P2=(-7,0)

1. find the slope
m = (0-(-7))/(-7-0) = -1

2. find the intercept b, using P1 coordinates (0,-7) and the computed slope m,

y=mx + b
-7= (-1)*0 + b
b = -7

P2 may also be used and the same b will be obtained

Therefore the equation of the line is

y = -1x -7 or

y = -x - 7

Answer 3

An equation in standard form means of the form:

y = mx + b

So what you do is you plug both points into that equation:

-7 = m(0) + b
0 = m(-7) + b

And solve for m and b.

In the first equation we see m drops out (because of the zero).
Therefore:
b = -7

So plug that value of b into the 2nd equation

0 = m(-7) - 7

Rearrange and solve for m.

7 = m(-7)
m = -1

So: y = -x - 7

Answer 4

The equation of line passing through (x1, y1), (x2 , y2)

y - y1 = m(x - x1)

where m is slope and is given by (y2 - y1)/(x2 - x1)

here x1=0, y1 = -7 and x2 = -7, y2 = 0

so slope, m = 0-(-7)/(-7 -0) = 7/-7 = -1

the equation of line

y - (-7) = -1(x - 0)

y + 7 = -x

y = -x - 7

Answer 5

Find the slope.

m=0+7/-7-0

m=7/-7

m=-1

y=mx+b

b=-7

y=-1x-7

That is your answer.

Answer 6

In y=mx+b , it is y= -1x -7, but i 4got how to convert it, hope this helps

Answer 7

y = -1x - 7
or
y= -x - 7

Answer 8

noooooo.............standard form is Ax+By=C