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A car and driver weighing 6010 N passes a sign stating "Bridge out 33.9 m ahead." She slams on the brakes, and the car decelerates at a constant rate of 14.6 m/s/s
The acceleration of gravity is 9.8 m/s/s
What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water (in units of J)?

2007-12-16 10:49:06 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

the mass of the vehicle and driver is
6010/9.8

F=m*a
so the force is
14.6*6010/9.8
8954 N

since she travels 33.9 m to stop, the work done is
8954*33.9
303529 J

How fast was she going when she slammed on the brakes?

303529=.5*6010/9.8*v^2

31.4 m/s or about 113 km/hr

j

2007-12-18 05:48:52 · answer #1 · answered by odu83 7 · 0 0

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