2007-12-16 10:47:36 · 4 answers · asked by zoe13faye 2 in Science & Mathematics ➔ Mathematics
Let x and y be the 2 numbers.
So,
x*y= 612
x-y=19
Using the 1st equation, x*y=612, solve for y, so
y=612/x... plug this value into the 2nd equation
x-y=19
x-(612/x)=19
x^2-19x-612=0
Solve using the quadratic formula or foiling
2007-12-16 10:52:35 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
xy=612, so x=612/y.
19=y-x=y-612/y. Multiply thru by y to obtain
y^2 - 19y - 612 = 0, which has solutions y=36 and -17. Then x is, respectively, 17 and -36.
2007-12-16 18:55:58 · answer #2 · answered by Nick S 6 · 0⤊ 0⤋
xy=612
x-y = 19
(19+y)y= 612
y^2 - 19y -612 = 0
by quadratic, y=36
so the numbers are 36 and 17
2007-12-16 18:54:32 · answer #3 · answered by b1gmuff 3 · 0⤊ 0⤋
(x)(x-19)=612
x^2-19x=612
X^2-19x-612=0
use the quadratic formula and you get x=36. x-19=17
the two numbers are 36 and 17, or -36 and -17.
2007-12-16 18:53:16 · answer #4 · answered by tateurrea 2 · 0⤊ 0⤋