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4(t + 5) = 7 – 3t

2007-12-16 10:23:48 · 4 answers · asked by Diamond E 1 in Science & Mathematics Mathematics

4 answers

4(t + 5) = 7 – 3t

expand the brackets on the left hand side:
4t + 20 = 7 - 3t

Move the -3t over to the left hand side and the 20 to the right hand side

7t = -13

Divide both sides by 7
t= -13/7

2007-12-16 10:27:22 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0 0

First, distribute the 4 through the left side:

4t + 20 = 7 - 3t

Now we want to get the t's on one side and the constants on the other, so first add 3t to both sides of the equation:

7t + 20 = 7

and then subtract 20 from each side:

7t = -13

then divide each side by 7 to isolate t:

t = -13/7

2007-12-16 10:29:43 · answer #2 · answered by dan131m 5 · 0 0

4(t+5)=7-3t, use the "rain bow" method for getting rid of the brackets by multiplying each term inside by the "4"

4t+20=7-3t
4t+20-20= 7-3t-20
4t+3t=7-3t-20+3t
7t=-13
t= -13/7

2007-12-16 10:29:34 · answer #3 · answered by Ace 3 · 0 0

just expand all the bracktes and then isolate t
4t+20=7-3t
4t+3t=7-20
7t=-13
t=-13/7

2007-12-16 10:26:26 · answer #4 · answered by Anonymous · 0 0

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